一、返回两个数组中的不同元素
- 使用
forEach
diffArr = (arr1, arr2) => {
let newArr = [];
arr1.forEach((itm) => {
let itmStr = itm.toString();
let temp = arr2.every(ele => itmStr !== ele.toString());
if (temp) {
newArr.push(itm);
}
});
arr2.forEach((itm) => {
let itmStr = itm.toString();
let temp = arr1.every(ele => itmStr !== ele.toString());
if (temp) {
newArr.push(itm);
}
});
return newArr;
};
- 使用
filter
diffArr = (marr1, marr2) => {
const eleIsNotInArr = (ele, arr) => arr.every(m => m !== ele)
let newArr1 = marr1.filter(x => eleIsNotInArr(x, marr2));
let newArr2 = marr2.filter(x => eleIsNotInArr(x, marr1));
return newArr1.concat(newArr2)
};
二、返回两个数组中的相同元素
- 使用
filter
getSameEle = (marr1, marr2) => {
const eleIsInArr = (ele, arr) => arr.some(m => m === ele);
return marr1.filter(x => eleIsInArr(x, marr2))
};
